What is the solution for (dy)/(dx)+3y=2xe^{-3x} ?

The solution for (dy)/(dx)+3y=2xe^{-3x} is y=(x^2)/(e^{3x)}+(c_{1})/(e^{3x)}

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(dy)/(dx)+3y=2xe^{-3x}

\frac{d y}{d x} + 3 y = 2 x e^{- 3 x}

y = \frac{x ^{2}}{e ^{3 x}} + \frac{c _{1}}{e ^{3 x}}

Solution steps

\frac{d y}{d x} + 3 y = 2 x e^{- 3 x}

Solve linear ODE:

y = \frac{x ^{2}}{e ^{3 x}} + \frac{c _{1}}{e ^{3 x}}

y = \frac{x ^{2}}{e ^{3 x}} + \frac{c _{1}}{e ^{3 x}}

n = 0 \sum \infty \frac{1}{1.0 2 ^{n}}

\frac{d}{d T} (\frac{7}{6} T + 17)

\frac{d y}{d x} = \frac{y x + y}{y x + x}

x d x - y d y = 0

\frac{\partial}{\partial z} (e^{y})

What is the solution for (dy)/(dx)+3y=2xe^{-3x} ?
The solution for (dy)/(dx)+3y=2xe^{-3x} is y=(x^2)/(e^{3x)}+(c_{1})/(e^{3x)}