What is the derivative of 3x^3-6x ?

The derivative of 3x^3-6x is 9x^2-6

What is the first derivative of 3x^3-6x ?

The first derivative of 3x^3-6x is 9x^2-6

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\frac{d}{d x} (3 x^{3} - 6 x)

9 x^{2} - 6

Solution steps

\frac{d}{d x} (3 x^{3} - 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (6 x)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (6 x) = 6

= 9 x^{2} - 6

\frac{d}{d x} (cos (x - a))

\int_{0}^{\frac{1}{5}} x arcsin (5 x) d x

\int e^{2 x^{2}} d x

x \to 0 lim (\frac{tan ( 2 x )}{5 x})

\int \frac{4 sin ( x )}{( 1 + cos ( x ) ) ^{2}} d x

What is the derivative of 3x^3-6x ?
The derivative of 3x^3-6x is 9x^2-6
What is the first derivative of 3x^3-6x ?
The first derivative of 3x^3-6x is 9x^2-6