What is the derivative of f(x)=2x^2-5x+3,\at a=2 ?

The derivative of f(x)=2x^2-5x+3,\at a=2 is 4x-5

What is the first derivative of f(x)=2x^2-5x+3,\at a=2 ?

The first derivative of f(x)=2x^2-5x+3,\at a=2 is 4x-5

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derivative of

f (x) = 2 x^{2} - 5 x + 3, at a = 2

4 x - 5

Solution steps

\frac{d}{d x} (2 x^{2} - 5 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (3) = 0

= 4 x - 5 + 0

Simplify

= 4 x - 5

\frac{\partial}{\partial x} (ln (2 x^{2} + x y))

\int \frac{1}{x 100 x ^{2} - 100} d x

f (x) = x^{9} e^{x}

y^{\frac{1}{2}} y^{^{'}} + y^{\frac{3}{2}} = 1

\frac{d}{d x} (e^{- x} sin (2 x))

What is the derivative of f(x)=2x^2-5x+3,\at a=2 ?
The derivative of f(x)=2x^2-5x+3,\at a=2 is 4x-5
What is the first derivative of f(x)=2x^2-5x+3,\at a=2 ?
The first derivative of f(x)=2x^2-5x+3,\at a=2 is 4x-5