What is the tangent of y^2=5x^4-x^2,(-1,2) ?

The tangent of y^2=5x^4-x^2,(-1,2) is y=-9/2 x-5/2

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tangent of y^2=5x^4-x^2,(-1,2)

tangent of

y^{2} = 5 x^{4} - x^{2}, (- 1, 2)

y = - \frac{9}{2} x - \frac{5}{2}

Solution steps

Find the slope of

y^{2} = 5 x^{4} - x^{2} : \frac{d y}{d x} = \frac{x ( 10 x ^{2} - 1 )}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{9}{2}

Find the line with slope m=

- \frac{9}{2}

and passing through

(- 1, 2) : y = - \frac{9}{2} x - \frac{5}{2}

y = - \frac{9}{2} x - \frac{5}{2}

\int \frac{1}{y ^{2} ( y ^{2} + 1 )} d y

M^{2} (\frac{C}{2} - \frac{M}{3})

y^{^{'}} = 0.002 y - 200, y (0) = 80000

e^{4 x^{2}}

x y^{^{'}} = y + 8 x^{2} sin (x)

What is the tangent of y^2=5x^4-x^2,(-1,2) ?
The tangent of y^2=5x^4-x^2,(-1,2) is y=-9/2 x-5/2