What is the integral from-1 to 1 of x^{-2} ?

The integral from-1 to 1 of x^{-2} is diverges

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integral from-1 to 1 of x^{-2}

\int_{- 1}^{1} x^{- 2} d x

diverges

Solution steps

\int_{- 1}^{1} x^{- 2} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 1}^{0} x^{- 2} d x + \int_{0}^{1} x^{- 2} d x

\int_{- 1}^{0} x^{- 2} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\frac{d}{d x} (\frac{( 4 x )}{( x + 1 ) ^{2}})

x \to 1 lim (∣ 3 x - 6 ∣)

\int_{0}^{0.5} arccos (x) d x

n = 0 \sum \infty 7 (\frac{1}{10})^{n}

\frac{d}{d x} (ln (5 x^{3}))

What is the integral from-1 to 1 of x^{-2} ?
The integral from-1 to 1 of x^{-2} is diverges