What is the integral of 20e^u ?

The integral of 20e^u is 20e^u+C

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integral of 20e^u

\int 20 e^{u} d u

20 e^{u} + C

Solution steps

\int 20 e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 20 e^{u}

Add a constant to the solution

= 20 e^{u} + C

\frac{d}{d x} (e^{x} - 4 x^{2})

x^{2} + x + 3

\int \frac{1}{2 y ^{2}} d y

\int_{0}^{3} (x^{2} + 1) d x

n = 0 \sum \infty \frac{3}{n}