What is the derivative of y=ln(sqrt(7x)) ?

The derivative of y=ln(sqrt(7x)) is 1/(2x)

What is the first derivative of y=ln(sqrt(7x)) ?

The first derivative of y=ln(sqrt(7x)) is 1/(2x)

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derivative of

y = ln (7 x)

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (ln (7 x))

Simplify

ln (7 x) : ln (7 x)

= \frac{d}{d x} (ln (7 x))

Apply the chain rule:

\frac{1}{7 x} \frac{d}{d x} (7 x)

= \frac{1}{7 x} \frac{d}{d x} (7 x)

\frac{d}{d x} (7 x) = \frac{7}{2 x}

= \frac{1}{7 x} \cdot \frac{7}{2 x}

Simplify

\frac{1}{7 x} \cdot \frac{7}{2 x} : \frac{1}{2 x}

= \frac{1}{2 x}

\frac{d}{d x} (cos (x) - 7 x)

n = 0 \sum \infty - 2^{n}

\frac{d}{d x} (x^{3} (x + 2))

\int 5 (5 x - 1)^{3} d x

\int e^{x} + x cos (y) d y

What is the derivative of y=ln(sqrt(7x)) ?
The derivative of y=ln(sqrt(7x)) is 1/(2x)
What is the first derivative of y=ln(sqrt(7x)) ?
The first derivative of y=ln(sqrt(7x)) is 1/(2x)