What is the solution for (dy)/(dx)=((xy+y^2+x^2))/(x^2) ?

The solution for (dy)/(dx)=((xy+y^2+x^2))/(x^2) is y=tan(ln(x)+c_{1})x

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(dy)/(dx)=((xy+y^2+x^2))/(x^2)

\frac{d y}{d x} = \frac{( x y + y ^{2} + x ^{2} )}{x ^{2}}

y = tan (ln (x) + c_{1}) x

Solution steps

\frac{d y}{d x} = \frac{( x y + y ^{2} + x ^{2} )}{x ^{2}}

Solve using substitution:

y = tan (ln (x) + c_{1}) x

y = tan (ln (x) + c_{1}) x

\frac{\partial}{\partial x} ((3 x + 4 y) e^{y})

\int_{1}^{x} t y + 3 d t

\int_{1}^{2} x^{5} ln (x) d x

2 x y d x + (2 + x^{2}) d y = 0

y^{^{''}} - 2 y^{^{'}} = x + 2 e^{x}

What is the solution for (dy)/(dx)=((xy+y^2+x^2))/(x^2) ?
The solution for (dy)/(dx)=((xy+y^2+x^2))/(x^2) is y=tan(ln(x)+c_{1})x