What is the derivative of cos(kx) ?

The derivative of cos(kx) is -sin(kx)k

What is the first derivative of cos(kx) ?

The first derivative of cos(kx) is -sin(kx)k

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\frac{d}{d x} (cos (k x))

- sin (k x) k

Solution steps

\frac{d}{d x} (cos (k x))

Apply the chain rule:

- sin (k x) \frac{d}{d x} (k x)

= - sin (k x) \frac{d}{d x} (k x)

\frac{d}{d x} (k x) = k

= - sin (k x) k

\int \frac{1 + sin ( x )}{sec ( x )} d x

\int \frac{x ^{2}}{4 + x} d x

y^{^{'}} = - y^{\frac{3}{2}}

\int \frac{x ^{5} + 1}{x ^{6} - x ^{4}} d x

e^{- x} y^{^{'}} = \frac{x}{y}

What is the derivative of cos(kx) ?
The derivative of cos(kx) is -sin(kx)k
What is the first derivative of cos(kx) ?
The first derivative of cos(kx) is -sin(kx)k