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Popular >

y^'=e^{2x-1}y^2

Solution

y^{^{'}} = e^{2 x - 1} y^{2}

Solution

y = - \frac{2}{e ^{2 x - 1} + c _{1}}

Solution steps

y^{'} (x) = e^{2 x - 1} y^{2}

Solve separable ODE:

y = - \frac{2}{e ^{2 x - 1} + c _{1}}

y = - \frac{2}{e ^{2 x - 1} + c _{1}}

Popular Examples

x y^{^{'}} - 2 y = x^{3} e^{x}

integral of (x^3)/(x^2+6x+9)

\int \frac{x ^{3}}{x ^{2} + 6 x + 9} d x

integral from 1 to infinity of 3e^{-3x}

\int_{1}^{\infty} 3 e^{- 3 x} d x

integral of x^3*e^{4x}

\int x^{3} \cdot e^{4 x} d x

\frac{d}{d y} (x^{2} y^{3})

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{2x-1}y^2 ?
The solution for y^'=e^{2x-1}y^2 is y=-2/(e^{2x-1)+c_{1}}