en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{''}+25x=0

Solution

x^{^{''}} + 25 x = 0

Solution

x = c_{1} cos (5 t) + c_{2} sin (5 t)

Solution steps

x^{''} (t) + 25 x = 0

Solve linear ODE:

x = c_{1} cos (5 t) + c_{2} sin (5 t)

x = c_{1} cos (5 t) + c_{2} sin (5 t)

Popular Examples

derivative of e^xcos(sqrt(x))

\frac{d}{d x} (e^{x} cos (x))

derivative of ln(e^x+7x+1)

\frac{d}{d x} (ln (e^{x} + 7 x + 1))

(\partial)/(\partial r)(r*cos(t))

\frac{\partial}{\partial r} (r \cdot cos (t))

integral from 2 to 1 of 12x^{-5}

\int_{2}^{1} 12 x^{- 5} d x

derivative of (sqrt(x)-1/(sqrt(x))^2)

\frac{d}{d x} ((x - \frac{1}{x})^{2})

Frequently Asked Questions (FAQ)

What is the solution for x^{''}+25x=0 ?
The solution for x^{''}+25x=0 is x=c_{1}cos(5t)+c_{2}sin(5t)