What is the integral of sin(pi/2 x) ?

The integral of sin(pi/2 x) is -2/pi cos(pi/2 x)+C

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integral of sin(pi/2 x)

\int sin (\frac{π}{2} x) d x

- \frac{2}{π} cos (\frac{π}{2} x) + C

Solution steps

\int sin (\frac{π}{2} x) d x

Apply u-substitution

: \int sin (u) \frac{2}{π} d u

= \int sin (u) \frac{2}{π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{π} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{2}{π} (- cos (u))

Substitute back

u = \frac{π}{2} x

= \frac{2}{π} (- cos (\frac{π}{2} x))

Simplify

= - \frac{2}{π} cos (\frac{π}{2} x)

Add a constant to the solution

= - \frac{2}{π} cos (\frac{π}{2} x) + C

\frac{d}{d x} (2 x^{3} e^{x} (x^{2} - 3 x + 1))

\int \frac{1}{y ^{2} 14 - y ^{2}} d y

\frac{2}{x}

6 \frac{d y}{d x} + 42 y = 7

\int_{1}^{4} (x + \frac{1}{x}) d x

What is the integral of sin(pi/2 x) ?
The integral of sin(pi/2 x) is -2/pi cos(pi/2 x)+C