What is (d^2)/(dx^2)(cos^2(5pix)) ?

The answer to (d^2)/(dx^2)(cos^2(5pix)) is -50pi^2cos(10pix)

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(d^2)/(dx^2)(cos^2(5pix))

\frac{d ^{2}}{d x ^{2}} (cos^{2} (5 π x))

- 50 π^{2} cos (10 π x)

Solution steps

\frac{d ^{2}}{d x ^{2}} (cos^{2} (5 π x))

\frac{d}{d x} (cos^{2} (5 π x)) = - 10 π cos (5 π x) sin (5 π x)

= \frac{d}{d x} (- 10 π cos (5 π x) sin (5 π x))

\frac{d}{d x} (- 10 π cos (5 π x) sin (5 π x)) = - 50 π^{2} cos (10 π x)

= - 50 π^{2} cos (10 π x)

\int 2 cos^{2} (x) tan^{3} (x) d x

\frac{d}{d x} (10 100 x - x^{2})

e^{k t} (\frac{d y}{d t} + k y) = 0

f (r) = 6 e^{r}

\int 128 tan^{4} (\frac{x}{2}) d x

What is (d^2)/(dx^2)(cos^2(5pix)) ?
The answer to (d^2)/(dx^2)(cos^2(5pix)) is -50pi^2cos(10pix)