What is (\partial)/(\partial x)(6/5-6/5 e^{-20x}) ?

The answer to (\partial)/(\partial x)(6/5-6/5 e^{-20x}) is 24e^{-20x}

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(\partial)/(\partial x)(6/5-6/5 e^{-20x})

\frac{\partial}{\partial x} (\frac{6}{5} - \frac{6}{5} e^{- 20 x})

24 e^{- 20 x}

Solution steps

\frac{\partial}{\partial x} (\frac{6}{5} - \frac{6}{5} e^{- 20 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (\frac{6}{5}) - \frac{\partial}{\partial x} (\frac{6}{5} e^{- 20 x})

\frac{\partial}{\partial x} (\frac{6}{5}) = 0

\frac{\partial}{\partial x} (\frac{6}{5} e^{- 20 x}) = - 24 e^{- 20 x}

= 0 - (- 24 e^{- 20 x})

Simplify

= 24 e^{- 20 x}

n = 2 \sum \infty \frac{3}{n \cdot ( n + 3 )}

\frac{3}{5} x^{\frac{5}{3}} - \frac{3}{4} x^{\frac{1}{3}} + 7

\int (t^{2})^{2} + (t)^{2} d t

n \to 0 lim (\frac{1}{n} sin (\frac{1}{n}))

x \to 0 + lim (- x)

What is (\partial)/(\partial x)(6/5-6/5 e^{-20x}) ?
The answer to (\partial)/(\partial x)(6/5-6/5 e^{-20x}) is 24e^{-20x}