What is the solution for y^{''}+25y=40sin(5x) ?

The solution for y^{''}+25y=40sin(5x) is y=c_{1}cos(5x)+c_{2}sin(5x)-4xcos(5x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+25y=40sin(5x)

y^{^{''}} + 25 y = 40 sin (5 x)

y = c_{1} cos (5 x) + c_{2} sin (5 x) - 4 x cos (5 x)

Solution steps

y^{''} (x) + 25 y = 40 sin (5 x)

Solve linear ODE:

y = c_{1} cos (5 x) + c_{2} sin (5 x) - 4 x cos (5 x)

y = c_{1} cos (5 x) + c_{2} sin (5 x) - 4 x cos (5 x)

2 (x + 6), - 6, - 2

\int 5 x^{2} + x x d x

\frac{s}{s ^{2} + 3 s + 1}

n = 0 \sum \infty \frac{n !}{e ^{n}}

\int x^{3} + 1 d x

What is the solution for y^{''}+25y=40sin(5x) ?
The solution for y^{''}+25y=40sin(5x) is y=c_{1}cos(5x)+c_{2}sin(5x)-4xcos(5x)