What is the integral from-infinity to 0 of 1/(3-5x) ?

The integral from-infinity to 0 of 1/(3-5x) is diverges

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integral from-infinity to 0 of 1/(3-5x)

\int_{- \infty}^{0} \frac{1}{3 - 5 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{3 - 5 x} d x

Compute the indefinite integral:

\int \frac{1}{3 - 5 x} d x = - \frac{1}{5} ln ∣ 3 - 5 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{3 - 5 x} d x =

diverges

= diverges

\int \frac{x ^{3} + 21}{x ^{2} + 5 x + 6} d x

\frac{\partial}{\partial x} (a x^{b} y^{1 - b})

\frac{d y}{d x} = x^{2} e^{x^{3}}

\frac{\partial}{\partial x} (4 sin (3 x))

x (x^{6} + 6)

What is the integral from-infinity to 0 of 1/(3-5x) ?
The integral from-infinity to 0 of 1/(3-5x) is diverges