What is (\partial)/(\partial x)(2x+ye^x) ?

The answer to (\partial)/(\partial x)(2x+ye^x) is 2+ye^x

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(\partial)/(\partial x)(2x+ye^x)

\frac{\partial}{\partial x} (2 x + y e^{x})

2 + y e^{x}

Solution steps

\frac{\partial}{\partial x} (2 x + y e^{x})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (y e^{x})

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (y e^{x}) = y e^{x}

= 2 + y e^{x}

\int_{0}^{0.1} x arctan (3 x) d x

\frac{d}{d x} (1. 5^{1.7 x})

(- 5, 1), (- 4, - 9)

\frac{d}{d x} (200 ln (\frac{x}{40}))

\int (3 t + 1) (t - 2) d t

What is (\partial)/(\partial x)(2x+ye^x) ?
The answer to (\partial)/(\partial x)(2x+ye^x) is 2+ye^x