What is the limit as x approaches 3 of 6/((x-3)^2) ?

The limit as x approaches 3 of 6/((x-3)^2) is infinity

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limit as x approaches 3 of 6/((x-3)^2)

x \to 3 lim (\frac{6}{( x - 3 ) ^{2}})

\infty

Solution steps

x \to 3 lim (\frac{6}{( x - 3 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 3 - lim (\frac{6}{( x - 3 ) ^{2}}) = \infty

x \to 3 + lim (\frac{6}{( x - 3 ) ^{2}}) = \infty

= \infty

\int_{- 2}^{8} \frac{1}{∣ 2 x ∣} d x

\int \frac{11 - 11 x}{1 - x} d x

f (x) = 6 x

\int 3 x^{2} sin (x^{3}) d x

y = x^{2} + 1, (- 4, 17)

What is the limit as x approaches 3 of 6/((x-3)^2) ?
The limit as x approaches 3 of 6/((x-3)^2) is infinity