What is (d^4)/(dx^4)(3e^{x^2}) ?

The answer to (d^4)/(dx^4)(3e^{x^2}) is 6(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})

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(d^4)/(dx^4)(3e^{x^2})

\frac{d ^{4}}{d x ^{4}} (3 e^{x^{2}})

6 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

Solution steps

\frac{d ^{4}}{d x ^{4}} (3 e^{x^{2}})

\frac{d}{d x} (3 e^{x^{2}}) = 6 e^{x^{2}} x

= \frac{d ^{3}}{d x ^{3}} (6 e^{x^{2}} x)

\frac{d}{d x} (6 e^{x^{2}} x) = 6 (2 e^{x^{2}} x^{2} + e^{x^{2}})

= \frac{d ^{2}}{d x ^{2}} (6 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

\frac{d}{d x} (6 (2 e^{x^{2}} x^{2} + e^{x^{2}})) = 6 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

= \frac{d}{d x} (6 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x))

\frac{d}{d x} (6 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)) = 6 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

= 6 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

4 y^{^{''}} - 4 y^{^{'}} + y = 0

n = 1 \sum \infty ln (\frac{1}{n ^{2}})

\frac{d}{d x} (2 x (3 x^{2} - 7)^{3})

x \to 3 lim (\frac{x ^{2} - 1}{x - 3})

\int \frac{z}{z - 1} d z

What is (d^4)/(dx^4)(3e^{x^2}) ?
The answer to (d^4)/(dx^4)(3e^{x^2}) is 6(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})