What is the integral of (sin^2(x)+cos^2(x)-1) ?

The integral of (sin^2(x)+cos^2(x)-1) is C

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integral of (sin^2(x)+cos^2(x)-1)

\int (sin^{2} (x) + cos^{2} (x) - 1) d x

C

Solution steps

\int sin^{2} (x) + cos^{2} (x) - 1 d x

Rewrite using trig identities

= \int 0 d x

Integral of a constant:

\int a d x = a x

= 0 \cdot x

Simplify

= 0

Add a constant to the solution

= 0 + C

= C

\int - \frac{6 x}{5} d x

y = (x^{3} - 25 x)^{14}

f (x) = (8 - x)^{6}

x \to 0 + lim (\frac{- 1}{x})

\frac{16 s + 5}{s ^{2} + 9}

What is the integral of (sin^2(x)+cos^2(x)-1) ?
The integral of (sin^2(x)+cos^2(x)-1) is C