What is laplacetransform 3sin(3t) ?

The answer to laplacetransform 3sin(3t) is 9/(s^2+9)

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laplacetransform 3sin(3t)

laplace transform

3 sin (3 t)

\frac{9}{s ^{2} + 9}

Solution steps

L {3 sin (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= 3 \cdot \frac{3}{s ^{2} + 9}

Refine

3 \frac{3}{s ^{2} + 9} : \frac{9}{s ^{2} + 9}

= \frac{9}{s ^{2} + 9}

\frac{d}{d x} ((x - 2)^{3} (6 - x)^{4})

\frac{d}{d x} (2^{x} sin (x))

\int cos (b + a x) d x

2 x^{2} y y^{^{'}} + 2 x y^{2} + 1 = 0

\int (4^{x}) d x

What is laplacetransform 3sin(3t) ?
The answer to laplacetransform 3sin(3t) is 9/(s^2+9)