What is the derivative of x^2+3x+9 ?

The derivative of x^2+3x+9 is 2x+3

What is the first derivative of x^2+3x+9 ?

The first derivative of x^2+3x+9 is 2x+3

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derivative of

x^{2} + 3 x + 9

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (9) = 0

= 2 x + 3 + 0

Simplify

= 2 x + 3

n = 1 \sum \infty \frac{x ^{n}}{n + 3}

\frac{1}{2 s ^{3}}

\int_{0}^{5} \frac{1}{x ^{\frac{18}{17}}} d x

\frac{d}{d x} (2^{x y})

e^{- 3 x}

What is the derivative of x^2+3x+9 ?
The derivative of x^2+3x+9 is 2x+3
What is the first derivative of x^2+3x+9 ?
The first derivative of x^2+3x+9 is 2x+3