What is the limit as x approaches 8 of ((sqrt(x)-2))/(x-8) ?

The limit as x approaches 8 of ((sqrt(x)-2))/(x-8) is diverges

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limit as x approaches 8 of ((sqrt(x)-2))/(x-8)

x \to 8 lim (\frac{( x - 2 )}{x - 8})

diverges

Solution steps

x \to 8 lim (\frac{x - 2}{x - 8})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 8 + lim (\frac{x - 2}{x - 8}) = \infty

x \to 8 - lim (\frac{x - 2}{x - 8}) = - \infty

= diverges

h \to 0 lim (\frac{f ( h ) ( h + 2 ) - 11}{h})

\frac{d}{d x} (\frac{36 x}{( x ^{2} + 9 ) ^{2}})

\frac{d}{d x} (\frac{1}{5} cos (5 x))

\int_{1200}^{1204} 0.1 d x

What is the limit as x approaches 8 of ((sqrt(x)-2))/(x-8) ?
The limit as x approaches 8 of ((sqrt(x)-2))/(x-8) is diverges