What is the (c_{2}sin(8t))^' ?

The (c_{2}sin(8t))^' is c_{2}cos(8t)*8

What is the first (c_{2}sin(8t))^' ?

The first (c_{2}sin(8t))^' is c_{2}cos(8t)*8

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(c_{2} sin (8 t))^{^{'}}

c_{2} cos (8 t) \cdot 8

Solution steps

(c_{2} sin (8 t))^{'}

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= c_{2} (sin (8 t))^{^{'}}

Apply the chain rule:

cos (8 t) (8 t)^{'}

= cos (8 t) (8 t)^{'}

(8 t)^{'} = 8

= c_{2} cos (8 t) \cdot 8

\int - 3 x^{5} d x

\int (x - 2) (x + 3) d x

f (x) = x^{\frac{1}{10}}

x \to 0 lim ((1 - 4 x)^{\frac{5}{x}})

(\frac{x}{2 - x})^{3}

What is the (c_{2}sin(8t))^' ?
The (c_{2}sin(8t))^' is c_{2}cos(8t)*8
What is the first (c_{2}sin(8t))^' ?
The first (c_{2}sin(8t))^' is c_{2}cos(8t)*8