What is the solution for (x^2-2y^2)dx+xydy=0 ?

The solution for (x^2-2y^2)dx+xydy=0 is y=xsqrt(1+c_{1)x^2},y=-xsqrt(1+c_{1)x^2}

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(x^2-2y^2)dx+xydy=0

(x^{2} - 2 y^{2}) d x + x y d y = 0

y = x 1 + c_{1} x^{2}, y = - x 1 + c_{1} x^{2}

Solution steps

(x^{2} - 2 y^{2}) d x + x y d y = 0

Solve Bernoulli ODE:

y = x 1 + c_{1} x^{2}, y = - x 1 + c_{1} x^{2}

y = x 1 + c_{1} x^{2}, y = - x 1 + c_{1} x^{2}

\frac{d}{d x} ((\frac{1}{3})^{2})

y^{^{'''}} - 6 y^{^{''}} = 3 - cos (x)

\frac{\partial}{\partial y} (y x^{2} + y^{2})

f (x) = - 2 x^{- 1} tan (x)

x \to 0 - lim (\frac{1}{x} - \frac{1}{e ^{x} - 1})

What is the solution for (x^2-2y^2)dx+xydy=0 ?
The solution for (x^2-2y^2)dx+xydy=0 is y=xsqrt(1+c_{1)x^2},y=-xsqrt(1+c_{1)x^2}