What is area y=x^3-x^2-12x,x=-3,x=0 ?

The answer to area y=x^3-x^2-12x,x=-3,x=0 is 99/4

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area y=x^3-x^2-12x,x=-3,x=0

area

y = x^{3} - x^{2} - 12 x, x = - 3, x = 0

\frac{99}{4}

Decimal Notation

24.75

Solution steps

Apply the area formula:

\int_{- 3}^{0} x^{3} - x^{2} - 12 x d x

Solve

\int_{- 3}^{0} x^{3} - x^{2} - 12 x d x : \frac{99}{4}

The area is:

= \frac{99}{4}

\frac{d}{d x} (\frac{- sin ^{3} ( ln ( x ) )}{x})

x (x - 1) y^{^{''}} - x y^{^{'}} + y = 0

- 2 t (6 t^{6} - 1)^{6}

\frac{x}{2 x - 1}

\int \frac{x - 2}{x ^{4} - x ^{2}} d x

What is area y=x^3-x^2-12x,x=-3,x=0 ?
The answer to area y=x^3-x^2-12x,x=-3,x=0 is 99/4