What is the derivative of (x^2-3^4) ?

The derivative of (x^2-3^4) is 8x(x^2-3)^3

What is the first derivative of (x^2-3^4) ?

The first derivative of (x^2-3^4) is 8x(x^2-3)^3

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\frac{d}{d x} ((x^{2} - 3)^{4})

8 x (x^{2} - 3)^{3}

Solution steps

\frac{d}{d x} ((x^{2} - 3)^{4})

Apply the chain rule:

4 (x^{2} - 3)^{3} \frac{d}{d x} (x^{2} - 3)

= 4 (x^{2} - 3)^{3} \frac{d}{d x} (x^{2} - 3)

\frac{d}{d x} (x^{2} - 3) = 2 x

= 4 (x^{2} - 3)^{3} \cdot 2 x

Simplify

= 8 x (x^{2} - 3)^{3}

f (x) = x + 8

(e^{2 x})^{^{'}}

e^{- 6 t}

\int - \frac{k}{m} d t

f (x) = \frac{x ^{2} + 3 x + 6}{9 x ^{4} + 9 x}

What is the derivative of (x^2-3^4) ?
The derivative of (x^2-3^4) is 8x(x^2-3)^3
What is the first derivative of (x^2-3^4) ?
The first derivative of (x^2-3^4) is 8x(x^2-3)^3