What is the derivative of x^3-9x ?

The derivative of x^3-9x is 3x^2-9

What is the first derivative of x^3-9x ?

The first derivative of x^3-9x is 3x^2-9

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\frac{d}{d x} (x^{3} - 9 x)

3 x^{2} - 9

Solution steps

\frac{d}{d x} (x^{3} - 9 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (9 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (9 x) = 9

= 3 x^{2} - 9

\int - \frac{2 x}{1 + x ^{2}} d x

f (x) = \frac{4}{x}, at x = - 2

\int_{1}^{8} 5 \frac{ln ( x )}{x ^{2}} d x

x \to \infty lim (0. 9^{x})

\int 2 sec (x) d x

What is the derivative of x^3-9x ?
The derivative of x^3-9x is 3x^2-9
What is the first derivative of x^3-9x ?
The first derivative of x^3-9x is 3x^2-9