What is the derivative of y=2cos(2x) ?

The derivative of y=2cos(2x) is -4sin(2x)

What is the first derivative of y=2cos(2x) ?

The first derivative of y=2cos(2x) is -4sin(2x)

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derivative of

y = 2 cos (2 x)

- 4 sin (2 x)

Solution steps

\frac{d}{d x} (2 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 2 (- sin (2 x) \cdot 2)

Simplify

= - 4 sin (2 x)

(x + 1)^{l n (x)}

\int \frac{x ^{2}}{16 - 25 x ^{2}} d x

\int \frac{( 16 x )}{( x ^{2} - 9 ) ^{5}} d x

x^{2} - \frac{x}{5}

\frac{d y}{d x} = y (5 - y), y = 6

What is the derivative of y=2cos(2x) ?
The derivative of y=2cos(2x) is -4sin(2x)
What is the first derivative of y=2cos(2x) ?
The first derivative of y=2cos(2x) is -4sin(2x)