What is the integral from-3 to-1 of 1/x ?

The integral from-3 to-1 of 1/x is -ln(3)

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integral from-3 to-1 of 1/x

\int_{- 3}^{- 1} \frac{1}{x} d x

- ln (3)

Decimal Notation

- 1.09861 \dots

Solution steps

\int_{- 3}^{- 1} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{- 3}^{- 1}

Compute the boundaries:

- ln (3)

= - ln (3)

x - \frac{1}{x}

\frac{d}{d x} (6 x ln (x))

\int \frac{e \frac{x}{2}}{x} d x

\frac{d}{d x} (\frac{6 ( x - 3 ) ^{2}}{3 x ^{2} - 9 x - 12})

\frac{d}{d x} (3^{x^{2} + 1})

What is the integral from-3 to-1 of 1/x ?
The integral from-3 to-1 of 1/x is -ln(3)