What is the tangent of y=4(x-1x)4,\at x=2 ?

The tangent of y=4(x-1x)4,\at x=2 is y=0

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tangent of y=4(x-1x)4,\at x=2

tangent of

y = 4 (x - 1 x) 4, at x = 2

y = 0

Solution steps

Find the tangent point:

(2, 0)

Find the slope of

y = 4 (x - 1 x) 4 : \frac{d y}{d x} = 0

Find the line with slope m=

0

and passing through

(2, 0) : y = 0

y = 0

\frac{d}{d x} (\frac{1 + x}{2 + x})

\int 4 z + z 1 - z^{2} d z

- 5 e^{x}

\int \frac{x ^{6}}{( 6 - x ^{7} ) ^{2}} d x

x \to 7 lim (∣ x - 7 ∣)

What is the tangent of y=4(x-1x)4,\at x=2 ?
The tangent of y=4(x-1x)4,\at x=2 is y=0