What is (\partial)/(\partial y)(2x^4y-2) ?

The answer to (\partial)/(\partial y)(2x^4y-2) is 2x^4

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(\partial)/(\partial y)(2x^4y-2)

\frac{\partial}{\partial y} (2 x^{4} y - 2)

2 x^{4}

Solution steps

\frac{\partial}{\partial y} (2 x^{4} y - 2)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{4} y) - \frac{\partial}{\partial y} (2)

\frac{\partial}{\partial y} (2 x^{4} y) = 2 x^{4}

\frac{\partial}{\partial y} (2) = 0

= 2 x^{4} - 0

Simplify

= 2 x^{4}

x \to 0 lim (\frac{6 sin ( x )}{x})

\int_{0}^{1} \frac{4}{x ^{2} + 1} d x

\int \frac{( x + 1 )}{x ^{3} + x} d x

\frac{d}{d x} (x (x^{2} + 1)^{\frac{1}{2}})

What is (\partial)/(\partial y)(2x^4y-2) ?
The answer to (\partial)/(\partial y)(2x^4y-2) is 2x^4