What is the derivative of 4/(5x^4+6\sqrt[3]{x^7}) ?

The derivative of 4/(5x^4+6\sqrt[3]{x^7}) is (-16+70x^{19/3})/(5x^5)

What is the first derivative of 4/(5x^4+6\sqrt[3]{x^7}) ?

The first derivative of 4/(5x^4+6\sqrt[3]{x^7}) is (-16+70x^{19/3})/(5x^5)

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\frac{- 16 + 70 x ^{\frac{19}{3}}}{5 x ^{5}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{4}{5 x ^{4}}) = - \frac{16}{5 x ^{5}}

= - \frac{16}{5 x ^{5}} + 14 x^{\frac{4}{3}}

Simplify

- \frac{16}{5 x ^{5}} + 14 x^{\frac{4}{3}} : \frac{- 16 + 70 x ^{\frac{19}{3}}}{5 x ^{5}}

= \frac{- 16 + 70 x ^{\frac{19}{3}}}{5 x ^{5}}

n = 1 \sum \infty (1 - \frac{5}{n})^{n}

\frac{4}{3} π x^{3}

sin (2 t)

\int e^{s i n (y)} d y

\int \frac{t ^{3} - 1}{2 t - 2} d t

What is the derivative of 4/(5x^4+6\sqrt[3]{x^7}) ?
The derivative of 4/(5x^4+6\sqrt[3]{x^7}) is (-16+70x^{19/3})/(5x^5)
What is the first derivative of 4/(5x^4+6\sqrt[3]{x^7}) ?
The first derivative of 4/(5x^4+6\sqrt[3]{x^7}) is (-16+70x^{19/3})/(5x^5)