What is inverse oflaplace 2/(s^2+4) ?

The answer to inverse oflaplace 2/(s^2+4) is sin(2t)

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inverse oflaplace 2/(s^2+4)

inverse laplace

\frac{2}{s ^{2} + 4}

sin (2 t)

Solution steps

L^{- 1} {\frac{2}{s ^{2} + 4}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{a}{s ^{2} + a ^{2}}} = sin (a t)

L^{- 1} {\frac{2}{s ^{2} + 2 ^{2}}} = sin (2 t)

= sin (2 t)

\frac{d}{d x} (I n (x + a^{2} + x^{2}))

\frac{d}{d x} (\frac{x ^{2} + 1}{x ^{2} - 1})

y^{^{'}} + 4 y = e^{- 4 t}

\frac{d}{d x} (\frac{7 x}{x ^{2} + 1})

\int \frac{1}{x ^{2} + 5} d x

What is inverse oflaplace 2/(s^2+4) ?
The answer to inverse oflaplace 2/(s^2+4) is sin(2t)