What is the derivative of sqrt(7x+5) ?

The derivative of sqrt(7x+5) is 7/(2sqrt(7x+5))

What is the first derivative of sqrt(7x+5) ?

The first derivative of sqrt(7x+5) is 7/(2sqrt(7x+5))

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\frac{d}{d x} (7 x + 5)

\frac{7}{2 7 x + 5}

Solution steps

\frac{d}{d x} (7 x + 5)

Apply the chain rule:

\frac{1}{2 7 x + 5} \frac{d}{d x} (7 x + 5)

= \frac{1}{2 7 x + 5} \frac{d}{d x} (7 x + 5)

\frac{d}{d x} (7 x + 5) = 7

= \frac{1}{2 7 x + 5} \cdot 7

Simplify

\frac{1}{2 7 x + 5} \cdot 7 : \frac{7}{2 7 x + 5}

= \frac{7}{2 7 x + 5}

y^{'} = y^{3} - 4 y

x \to 0 + lim ((3 x)^{5 x})

\int \frac{1}{1 - y ^{2}} d y

f (x) = \frac{1}{- 3 + ( 2 x + 1 ) ^{2}}

\frac{d y}{d x} = \frac{x ^{4} - 6 y}{x}

What is the derivative of sqrt(7x+5) ?
The derivative of sqrt(7x+5) is 7/(2sqrt(7x+5))
What is the first derivative of sqrt(7x+5) ?
The first derivative of sqrt(7x+5) is 7/(2sqrt(7x+5))