What is the derivative of 2x^3-5x ?

The derivative of 2x^3-5x is 6x^2-5

What is the first derivative of 2x^3-5x ?

The first derivative of 2x^3-5x is 6x^2-5

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\frac{d}{d x} (2 x^{3} - 5 x)

6 x^{2} - 5

Solution steps

\frac{d}{d x} (2 x^{3} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (5 x) = 5

= 6 x^{2} - 5

\int \frac{2}{( x - 2 ) ^{2}} d x

x = y^{2} - 8, x = 8

\int (\frac{x + 4}{x}) d x

\frac{\partial}{\partial x} (4 x^{\frac{1}{2}} + y)

\int \frac{( x ^{2} - 3 x + 2 )}{x + 1} d x

What is the derivative of 2x^3-5x ?
The derivative of 2x^3-5x is 6x^2-5
What is the first derivative of 2x^3-5x ?
The first derivative of 2x^3-5x is 6x^2-5