What is the derivative of f(x)=(2x^2-4)-1 ?

The derivative of f(x)=(2x^2-4)-1 is 4x

What is the first derivative of f(x)=(2x^2-4)-1 ?

The first derivative of f(x)=(2x^2-4)-1 is 4x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = (2 x^{2} - 4) - 1

4 x

Solution steps

\frac{d}{d x} ((2 x^{2} - 4) - 1)

Simplify

(2 x^{2} - 4) - 1 : 2 x^{2} - 5

= \frac{d}{d x} (2 x^{2} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5) = 0

= 4 x - 0

Simplify

= 4 x

\int (x + sin (x)) d x

\frac{d ^{2}}{d x ^{2}} (e^{3 e^{x}})

\int e^{x} tan^{4} (e^{x}) d x

\frac{d}{d x} (\frac{6}{( 2 - x ) ^{4}})

\int \frac{1}{3 x ^{2} - 2} d x

What is the derivative of f(x)=(2x^2-4)-1 ?
The derivative of f(x)=(2x^2-4)-1 is 4x
What is the first derivative of f(x)=(2x^2-4)-1 ?
The first derivative of f(x)=(2x^2-4)-1 is 4x