What is (\partial)/(\partial x)(sqrt(8-3x^2-y^2)) ?

The answer to (\partial)/(\partial x)(sqrt(8-3x^2-y^2)) is -(3x)/(sqrt(8-3x^2-y^2))

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(\partial)/(\partial x)(sqrt(8-3x^2-y^2))

\frac{\partial}{\partial x} (8 - 3 x^{2} - y^{2})

- \frac{3 x}{8 - 3 x ^{2} - y ^{2}}

Solution steps

\frac{\partial}{\partial x} (8 - 3 x^{2} - y^{2})

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 8 - 3 x ^{2} - y ^{2}} \frac{\partial}{\partial x} (8 - 3 x^{2} - y^{2})

= \frac{1}{2 8 - 3 x ^{2} - y ^{2}} \frac{\partial}{\partial x} (8 - 3 x^{2} - y^{2})

\frac{\partial}{\partial x} (8 - 3 x^{2} - y^{2}) = - 6 x

= \frac{1}{2 8 - 3 x ^{2} - y ^{2}} (- 6 x)

Simplify

\frac{1}{2 8 - 3 x ^{2} - y ^{2}} (- 6 x) : - \frac{3 x}{8 - 3 x ^{2} - y ^{2}}

= - \frac{3 x}{8 - 3 x ^{2} - y ^{2}}

\int \frac{x ^{2} + 2 x - 6}{x ^{3} - x} d x

\frac{d}{d x} (e^{x \cdot l n (x)})

\frac{d}{d x} (\frac{1}{x ln ^{2} ( x )})

y = tan (12 x^{2}), at x = π

(x^{2})^{2}

What is (\partial)/(\partial x)(sqrt(8-3x^2-y^2)) ?
The answer to (\partial)/(\partial x)(sqrt(8-3x^2-y^2)) is -(3x)/(sqrt(8-3x^2-y^2))