What is the solution for (dy)/(dx)=e^{y+2x} ?

The solution for (dy)/(dx)=e^{y+2x} is y=-ln(-1/2 e^{2x}-c_{1})

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(dy)/(dx)=e^{y+2x}

\frac{d y}{d x} = e^{y + 2 x}

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

Solution steps

\frac{d y}{d x} = e^{y + 2 x}

Solve separable ODE:

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

y = - ln (- \frac{1}{2} e^{2 x} - c_{1})

y^{^{''}} + y^{^{'}} = 2 e^{x} + 14

\int 8 x - 2 x^{2} d x

\frac{\partial}{\partial y} (cos (x y) - e^{z} + 2)

\frac{\partial}{\partial y} (r cos (y))

\frac{d}{d x} (4 x^{2} - 5 x + 4)

What is the solution for (dy)/(dx)=e^{y+2x} ?
The solution for (dy)/(dx)=e^{y+2x} is y=-ln(-1/2 e^{2x}-c_{1})