What is the limit as n approaches infinity of-10^n ?

The limit as n approaches infinity of-10^n is -infinity

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limit as n approaches infinity of-10^n

n \to \infty lim (- 1 0^{n})

- \infty

Solution steps

n \to \infty lim (- 1 0^{n})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - n \to \infty lim (1 0^{n})

Apply the common limit:

x \to \infty lim (a^{x}) = \infty, a > 1

= - \infty

x \to - 3 lim (\frac{x}{x + 5})

\frac{d}{d x} ((x^{2} - 3)^{3})

\int \frac{14}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

\int ln (x^{6}) d x

\frac{d y}{d t} = \frac{3 ( y + 1 )}{t ^{2} + 5 t + 6}

What is the limit as n approaches infinity of-10^n ?
The limit as n approaches infinity of-10^n is -infinity