What is the tangent of x^3+y^3=9,(1,2) ?

The tangent of x^3+y^3=9,(1,2) is y=-1/4 x+9/4

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tangent of x^3+y^3=9,(1,2)

tangent of

x^{3} + y^{3} = 9, (1, 2)

y = - \frac{1}{4} x + \frac{9}{4}

Solution steps

Find the slope of

x^{3} + y^{3} = 9 : \frac{d y}{d x} = - \frac{x ^{2}}{( 9 - x ^{3} ) ^{\frac{2}{3}}}

Compute the slope of

x^{3} + y^{3} = 9

(1, 2) : m = - \frac{1}{4}

Find the line with slope m=

- \frac{1}{4}

and passing through

(1, 2) : y = - \frac{1}{4} x + \frac{9}{4}

y = - \frac{1}{4} x + \frac{9}{4}

\int (a^{2} - x^{2}) d x

\frac{d}{d x} (\frac{ln ( x )}{x ^{\frac{3}{2}}})

x \to 0 - lim (3 - \frac{4}{x})

x^{3}, - 1

\int \frac{e ^{2 x}}{5 + e ^{x}} d x

What is the tangent of x^3+y^3=9,(1,2) ?
The tangent of x^3+y^3=9,(1,2) is y=-1/4 x+9/4