What is the derivative of 3x^3-64x ?

The derivative of 3x^3-64x is 9x^2-64

What is the first derivative of 3x^3-64x ?

The first derivative of 3x^3-64x is 9x^2-64

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\frac{d}{d x} (3 x^{3} - 64 x)

9 x^{2} - 64

Solution steps

\frac{d}{d x} (3 x^{3} - 64 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (64 x)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (64 x) = 64

= 9 x^{2} - 64

x \to 1 + lim (tan (\frac{π x}{2}))

x \to \frac{1}{2} lim (x)

\frac{d}{d x} (- x \cdot ln (x))

x \to 0 lim (\frac{2. 8 ^{x} - 1}{x})

\int \frac{1}{2 u} d u

What is the derivative of 3x^3-64x ?
The derivative of 3x^3-64x is 9x^2-64
What is the first derivative of 3x^3-64x ?
The first derivative of 3x^3-64x is 9x^2-64