What is the derivative of f(x)=(x^2-9)^2 ?

The derivative of f(x)=(x^2-9)^2 is 4x(x^2-9)

What is the first derivative of f(x)=(x^2-9)^2 ?

The first derivative of f(x)=(x^2-9)^2 is 4x(x^2-9)

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derivative of

f (x) = (x^{2} - 9)^{2}

4 x (x^{2} - 9)

Solution steps

\frac{d}{d x} ((x^{2} - 9)^{2})

Apply the chain rule:

2 (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

= 2 (x^{2} - 9) \frac{d}{d x} (x^{2} - 9)

\frac{d}{d x} (x^{2} - 9) = 2 x

= 2 (x^{2} - 9) \cdot 2 x

Simplify

= 4 x (x^{2} - 9)

\frac{d y}{d x} = \frac{3 y ^{2} cot ( x ) + sin ( x ) cos ( x )}{2 y}

x \to 10 lim (\frac{8}{( x - 10 ) ^{2}})

\frac{d}{d x} (\frac{2 x + 1}{2 x - 1})

(10 x e^{x} - 5 x y) d x + (2 x y - 5 x^{2}) d y = 0

x^{2} y^{^{''}} - 2 y = 3 x^{2} - 1

What is the derivative of f(x)=(x^2-9)^2 ?
The derivative of f(x)=(x^2-9)^2 is 4x(x^2-9)
What is the first derivative of f(x)=(x^2-9)^2 ?
The first derivative of f(x)=(x^2-9)^2 is 4x(x^2-9)