What is the solution for xy^'+3y=(e^x)/x ?

The solution for xy^'+3y=(e^x)/x is y=(e^x)/(x^2)-(e^x)/(x^3)+(c_{1})/(x^3)

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xy^'+3y=(e^x)/x

x y^{^{'}} + 3 y = \frac{e ^{x}}{x}

y = \frac{e ^{x}}{x ^{2}} - \frac{e ^{x}}{x ^{3}} + \frac{c _{1}}{x ^{3}}

Solution steps

x y^{'} (x) + 3 y = \frac{e ^{x}}{x}

Solve linear ODE:

y = \frac{e ^{x}}{x ^{2}} - \frac{e ^{x}}{x ^{3}} + \frac{c _{1}}{x ^{3}}

y = \frac{e ^{x}}{x ^{2}} - \frac{e ^{x}}{x ^{3}} + \frac{c _{1}}{x ^{3}}

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What is the solution for xy^'+3y=(e^x)/x ?
The solution for xy^'+3y=(e^x)/x is y=(e^x)/(x^2)-(e^x)/(x^3)+(c_{1})/(x^3)