What is the integral of sec(2x)tan(2x) ?

The integral of sec(2x)tan(2x) is 1/2 cos(2x)+1/2 sin(2x)tan(2x)+C

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integral of sec(2x)tan(2x)

\int sec (2 x) tan (2 x) d x

\frac{1}{2} cos (2 x) + \frac{1}{2} sin (2 x) tan (2 x) + C

Solution steps

\int sec (2 x) tan (2 x) d x

Rewrite using trig identities

= \int \frac{sin ( 2 x )}{cos ^{2} ( 2 x )} d x

Apply Integration By Parts

: - \int sin (2 x) d x + \frac{1}{2} sin (2 x) tan (2 x)

= - \int sin (2 x) d x + \frac{1}{2} sin (2 x) tan (2 x)

\int sin (2 x) d x = - \frac{1}{2} cos (2 x)

= - (- \frac{1}{2} cos (2 x)) + \frac{1}{2} sin (2 x) tan (2 x)

Simplify

= \frac{1}{2} cos (2 x) + \frac{1}{2} sin (2 x) tan (2 x)

Add a constant to the solution

= \frac{1}{2} cos (2 x) + \frac{1}{2} sin (2 x) tan (2 x) + C

\int x \cdot e^{2 x} d x

\int 2 sin (x) d x

\int cos^{3} (x) cos (3 x) d x

n \to \infty lim (\frac{1}{n ^{2} + 2 n - n})

\frac{sec ( x )}{7 + sec ( x )}

What is the integral of sec(2x)tan(2x) ?
The integral of sec(2x)tan(2x) is 1/2 cos(2x)+1/2 sin(2x)tan(2x)+C