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Popular >

derivative of 3(x^2+y^2^2)

Solution

\frac{d}{d x} (3 (x^{2} + y^{2})^{2})

Solution

6 (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

Solution steps

\frac{d}{d x} (3 (x^{2} + y^{2})^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} ((x^{2} + y^{2})^{2})

Apply the chain rule:

2 (x^{2} + y^{2}) \frac{d}{d x} (x^{2} + y^{2})

= 2 (x^{2} + y^{2}) \frac{d}{d x} (x^{2} + y^{2})

\frac{d}{d x} (x^{2} + y^{2}) = 2 x + 2 y \frac{d y}{d x}

= 3 \cdot 2 (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

Simplify

= 6 (x^{2} + y^{2}) (2 x + 2 y \frac{d y}{d x})

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x \to 2 lim (\frac{x}{( x - 2 )})

integral of (20)/(xsqrt(1+2x))

\int \frac{20}{x 1 + 2 x} d x

Frequently Asked Questions (FAQ)

What is the derivative of 3(x^2+y^2^2) ?
The derivative of 3(x^2+y^2^2) is 6(x^2+y^2)(2x+2y(dy)/(dx))
What is the first derivative of 3(x^2+y^2^2) ?
The first derivative of 3(x^2+y^2^2) is 6(x^2+y^2)(2x+2y(dy)/(dx))