What is the solution for xy^'+y=14sqrt(x) ?

The solution for xy^'+y=14sqrt(x) is y=(28x^{1/2})/3+(c_{1})/x

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xy^'+y=14sqrt(x)

x y^{^{'}} + y = 14 x

y = \frac{28 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

Solution steps

x y^{'} (x) + y = 14 x

Solve linear ODE:

y = \frac{28 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

y = \frac{28 x ^{\frac{1}{2}}}{3} + \frac{c _{1}}{x}

\int e^{3 x + 9} - 3 x^{2} d x

y^{^{''}} + 4 y = 8

\int 2 + cos (x) d x

x \to 2 lim (3 x^{2} - 7 x + 5)

\int sec^{4} (3 x) d x

What is the solution for xy^'+y=14sqrt(x) ?
The solution for xy^'+y=14sqrt(x) is y=(28x^{1/2})/3+(c_{1})/x