What is the derivative of 2x^3-x^2+3x ?

The derivative of 2x^3-x^2+3x is 6x^2-2x+3

What is the first derivative of 2x^3-x^2+3x ?

The first derivative of 2x^3-x^2+3x is 6x^2-2x+3

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\frac{d}{d x} (2 x^{3} - x^{2} + 3 x)

6 x^{2} - 2 x + 3

Solution steps

\frac{d}{d x} (2 x^{3} - x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= 6 x^{2} - 2 x + 3

y = x^{2} + 5

\int e^{- x} (1 - x) d x

\frac{\partial}{\partial x} (\frac{x}{x ^{7} - y ^{6}})

\int (x^{2} - 5)^{5} (2 x) d x

\frac{d}{d x} (\frac{5}{( 4 x ) ^{- 2}})

What is the derivative of 2x^3-x^2+3x ?
The derivative of 2x^3-x^2+3x is 6x^2-2x+3
What is the first derivative of 2x^3-x^2+3x ?
The first derivative of 2x^3-x^2+3x is 6x^2-2x+3