What is the limit as x approaches+(-2)-of 1/(x^2-4) ?

The limit as x approaches+(-2)-of 1/(x^2-4) is infinity

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limit as x approaches+(-2)-of 1/(x^2-4)

x \to + (- 2) - lim (\frac{1}{x ^{2} - 4})

\infty

Solution steps

x \to - 2 - lim (\frac{1}{x ^{2} - 4})

For

x

approaching

- 2

from the left

, x < - 2 \Rightarrow x^{2} - 4 > 0

The denominator is a positive quantity approaching 0 from the right

= \infty

\frac{d}{d x} (cos (wt))

\int \frac{ln ^{2} ( x )}{x} d x

x 5^{6 x + 1}

f (x) = \frac{x ^{2} - 1}{x + 3}

\frac{\partial}{\partial x} (6 x y + e^{x} ln (y) - 5)

What is the limit as x approaches+(-2)-of 1/(x^2-4) ?
The limit as x approaches+(-2)-of 1/(x^2-4) is infinity