What is the derivative of 2xln(2x+x) ?

The derivative of 2xln(2x+x) is 2ln(2x)+3

What is the first derivative of 2xln(2x+x) ?

The first derivative of 2xln(2x+x) is 2ln(2x)+3

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\frac{d}{d x} (2 x ln (2 x) + x)

2 ln (2 x) + 3

Solution steps

\frac{d}{d x} (2 x ln (2 x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x ln (2 x)) + \frac{d x}{d x}

\frac{d}{d x} (2 x ln (2 x)) = 2 (ln (2 x) + 1)

\frac{d x}{d x} = 1

= 2 (ln (2 x) + 1) + 1

Simplify

2 (ln (2 x) + 1) + 1 : 2 ln (2 x) + 3

= 2 ln (2 x) + 3

\frac{d y}{d x} - \frac{2 x}{2 - x ^{2}} \cdot y = e^{x}, y (2) = 4

f (x) = 3 0^{3} - 3 x^{2} + 12 x - 74

\frac{d}{d x} (6 e^{- 2 x})

x \to - 2 + lim (\frac{x + 3}{x + 2})

\frac{d}{d x} (x^{3} (3 x + 1)^{6})

What is the derivative of 2xln(2x+x) ?
The derivative of 2xln(2x+x) is 2ln(2x)+3
What is the first derivative of 2xln(2x+x) ?
The first derivative of 2xln(2x+x) is 2ln(2x)+3